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Fix (de)serialize enums into QDataStream.

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It is very important to use exactly the same way across all Qt versions we need to support. Otherwise, it will break interchange between Valentina versions built on different Qt versions.
This commit is contained in:
Roman Telezhynskyi 2020-05-09 12:36:03 +03:00
parent ab569feff8
commit a009e25004
1 changed files with 11 additions and 15 deletions
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26
src/libs/vmisc/vdatastreamenum.h
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@ -34,26 +34,22 @@
// (de)serialize enums into QDataStream // (de)serialize enums into QDataStream
// It is very important to use exactly the same way across all Qt versions we need to support. Otherwise, it will break
// interchange between Valentina versions built on different Qt versions.
#if QT_VERSION < QT_VERSION_CHECK(5, 14, 0) #if QT_VERSION < QT_VERSION_CHECK(5, 14, 0)
//a function that can serialize any enum into QDataStream template <typename T>
//it stores the enum in a qint64 typename std::enable_if<std::is_enum<T>::value, QDataStream &>::type&
template<typename Enum, operator<<(QDataStream &s, const T &t)
typename = typename std::enable_if<std::is_enum<Enum>::value>::type>
inline QDataStream& operator<<(QDataStream& stream, const Enum& e)
{ {
return stream << static_cast<qint64>(e); return s << static_cast<typename std::underlying_type<T>::type>(t);
} }
//a function that can deserialize any enum from QDataStream template <typename T>
//it reads the enum as if it was stored in qint64 typename std::enable_if<std::is_enum<T>::value, QDataStream &>::type&
template<typename Enum, operator>>(QDataStream &s, T &t)
typename = typename std::enable_if<std::is_enum<Enum>::value>::type>
inline QDataStream& operator>>(QDataStream& stream, Enum& e)
{ {
qint64 v; return s >> reinterpret_cast<typename std::underlying_type<T>::type &>(t);
stream >> v;
e = static_cast<Enum>(v);
return stream;
} }
#endif #endif